Fluid Power Journal

Problem: Total Energy Needed

What is the total energy in Joules needed to be dissipated by a shock absorber that is positioned under a hoist that releases a free-falling load of 100 kg, 1 meter above the shock absorber and the stroke of the shock absorber is .1 meters?

See the Solution

E (Total) = (m x g x h) + (m x g x S)

E (total) = Total energy due to free falling object (Joules)

M = Mass (kg)

G = Gravitational acceleration

(9.8m/sec²)

H = Height of object above shock absorber (meters)

S = Stroke length of shock absorber (meters)

E = (100 x 9.8 x 1) + (100 x 9.8 x .1)

(980) + (98) = 1078 Joules

Winner of this Air Teaser: John Krebsbach, FPE Automation

Deadline past. Not available for submissions.

By Ernie Parker, AI, AJPP, AJPPCC, S, MT, MM, MIH, MIP, MMH

This teaser is printed in the Fluid Power Journal. Those who submit the correct answer before the deadline will have their names printed in the Society Page newsletter and in Fluid Power Journal. The winners will also be entered into a drawing for a special gift.

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