Fluid Power Journal

Problem: Cylinder Retraction

Neglecting pilot line sizes, approximately how many seconds after pushing the start button will the cylinder start to retract?

air teaser

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By Ernie Parker, AI, AJPP, AJPPCC, S, MT, MM, MIH, MIP, MMH, Fluid Power Instructor, Hennepin Technical College, EParker@Hennepintech.edu

This teaser is printed in the Fluid Power Journal. Those who submit the correct answer before the deadline will have their names printed in the Society Page newsletter and in Fluid Power Journal. The winners will also be entered into a drawing for a special gift.

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4 thoughts on “Problem: Cylinder Retraction”

  1. Greg Gentile says:

    5.2 seconds

  2. Steve West says:

    The formula to use is: T = [V x( Pmax – Pmin) ] / 14.7 x Qscfm
    Using the 231/1728 conversion formula, the quart has a capacity of .0334201 cubi feet.
    T = [.0334201 (25 – 0)] / 14.7 (.05)
    T = .8355025/ .735 =1.136738 minutes or 68 seconds required before the cylinder starts to retract.

    1. Nate P says:

      T (Minutes) = [V acf x( Pmax – Pmin) ] / 14.7 x Qscfm
      Using the (231 /1728)/4 formula, one quart has a capacity of .0334201 actual cubic ft
      T = [.033 (86-0)] / 14.7 (.05)
      T = 232 seconds before the cylinder starts to retract.

      Cylinder starts retracted in this circuit. Pressing the start button extends the cylinder , 100 psi pilot holds the start button and starts a time delay to retract. The one quart bottle will need to reach 86 psi to shift the 5 way , exhausting the pressure from the start button pilot and 1 qt bottle. 86 psi + 15 psi spring = 101 psi . 5 way returns to its normal position with the cylinder retracted.

  3. Nate P says:

    232 sectonds

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